However, none of this is considered the best approach these days, with the advent of list comprehensions and generator expressions. Here's the old approach (shown above) and the shiny new modern Pythonic approach (requires Python 2.4):
>>> theList = range(10) >>> import operator >>> reduce(operator.add, map(str, theList)) '0123456789' >>> ''.join(str(x) for x in theList) '0123456789'
Also worth noting is that the shiny new modern version is also the faster version:
$ python -m timeit -s "import operator; L = range(10000)" "reduce(operator.add, map(str, L))"
10 loops, best of 3: 89.9 msec per loop
$ python -m timeit -s "L = range(10000)" "''.join(str(x) for x in L)" 100 loops, best of 3: 15.3 msec per loop
[run with Python 2.4 on a 2.26GHz Pentium 4]
Steve -- http://mail.python.org/mailman/listinfo/python-list
