You can do this without regular expressions if you like
>>> uptime='12:12:05 up 21 days, 16:31, 10 users, load average:
0.01, 0.02, 0.04'
>>> load = uptime[uptime.find('load average:'):]
>>> load
'load average: 0.01, 0.02, 0.04'
>>> load = load.split(':')
>>> load
['load average', ' 0.01, 0.02, 0.04']
>>> load[1].split(',')
[' 0.01', ' 0.02', ' 0.04']
One liner:
>>> uptime[uptime.find('load average:'):].split(':')[1].split(',')[0]
' 0.01'
On Tue, 14 Dec 2004 23:16:43 -0700, Michael McGarry
<[EMAIL PROTECTED]> wrote:
> Hi,
>
> I am horrible with Regular Expressions, can anyone recommend a book on it?
>
> Also I am trying to parse the following string to extract the number
> after load average.
>
> ".... load average: 0.04, 0.02, 0.01"
>
> how can I extract this number with RE or otherwise?
>
> Michael
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> http://mail.python.org/mailman/listinfo/python-list
>
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