Paul Rubin wrote: > > > median = lambda x: x.sort() or x[len(x)//2] > > Yucch!! > > median = x.sorted()[len(x)//2]
that doesn't do the same thing, and doesn't work on pre-2.4 releases. try again. (learning how "or" and "and" works in Python doesn't hurt, either; "value or value" is a very common idiom in Python code) </F> -- http://mail.python.org/mailman/listinfo/python-list
