On Sun, 05 Dec 2004 12:59:40 +0200, Roie Kerstein
<[EMAIL PROTECTED]> wrote:
Hello!
I want to compute a**b%c for very long numbers.
Computing a**b and then applying modulu is not practical, since it takes
ages.
There is a built-in optional parameter to the long.__pow__(a,b[,modulu]),
and it works well.
My question is: How can I write it is a form of an expression, like a**b?
AFAIK you can't.
I prefer not to fill my script with calls of the form
long.__pow__(a,b,c).
That's a bit ugly, yes; pow is also a builtin, e.g.:
pow(21,443,2)==1
--
Mitja
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