Darren Dale <[EMAIL PROTECTED]> writes: > I'm stuck. I'm trying to make this: > > file://C:%5Cfolder1%5Cfolder2%5Cmydoc1.pdf,file://C > %5Cfolderx%5Cfoldery%5Cmydoc2.pdf > > (no linebreaks) look like this: > > ./mydoc1.pdf,./mydoc2.pdf > > my regular expression abilities are dismal.
This works for the example string you gave: newstring = re.sub(r'[^,]*%5[Cc]', './', examplestring) This replaces all instances of zero or more non-commas that are followed by '%5C' or '%5c' with './'. Greediness causes the pattern to replace everything up to the last '%5C' before a comma or the end of the string. Regular expressions aren't the only way to do what you want. Python has standard modules for parsing URLs and file paths -- take a look at urlparse, urllib/urllib2, and os.path. -- Michael Fuhr http://www.fuhr.org/~mfuhr/ -- http://mail.python.org/mailman/listinfo/python-list
