Steven Bethard wrote: > def __eq__(self, other): > """x.__eq__(y) <==> x == y""" > return (isinstance(other, self.__class__) > and self.__dict__ == other.__dict__)
This results in an asymmetry: >>> from bunch import Bunch >>> class B(Bunch): pass ... >>> B().__eq__(Bunch()) False >>> Bunch().__eq__(B()) True With indirect use of __eq__() this puzzling behaviour disappears: >>> B() == Bunch() False >>> Bunch() == B() False Whether this is intended, I don't know. If someone can enlighten me... In any case I would prefer self.__class__ == other.__class__ over isinstance(). Peter -- http://mail.python.org/mailman/listinfo/python-list
