On Tue, Feb 15, 2022 at 05:39:33AM -0600, Tim Peters wrote:
> ([^s]|s(?!pam))*spam
>
> Bingo. That pattern is easy enough to understand
You and I have very different definitions of the word "easy" :-)
> (if not to invent the
> first time): we can chew up a character if it's not an "s", or if it
> is an "s" but one _not_ followed immediately by "pam".
It is times like this that I am reminded why I prefer to just call
string.find("spam") :-)
--
Steve
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