On Fri, May 28, 2021 at 04:20:15AM +1000, Chris Angelico wrote:
> def f():
> static x = 0
> x += 1
> yield x
>
> next(f())
> next(f())
> next(f())
>
> will yield 1 every time?
I think that this example has just about convinced me that Chris'
approach is correct. I wasn't thinking about generators or recursion.
I think that closure nonlocals are almost as fast as locals, so we might
be able to use the closure mechanism to get this. Something vaguely
like this:
def func():
static var = initial
body
is transformed into:
def factory():
var = initial
def func():
nonlocal var
body
return func
func = factory()
except that the factory is never actually exposed to Python code.
It would be nice if there was some way to introspect the value of `var`
but if there is a way to do it I don't know it.
We might not even need new syntax if we could do that transformation
using a decorator.
@static(var=initial)
def func():
body
--
Steve
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