I dislike adding more operator overload to builtin types.
str is not commutative, but it satisfies a in (a+b), and b in (a+b).
There are no loss.
In case of dict + dict, it not only sum. There may be loss value.
{"a":1} + {"a":2} = ?
In case of a.update(b), it's clear that b wins.
In case of a + b, "which wins" or "exception raised on duplicated key?" is
unclear to me.
Regards,
On Thu, Feb 28, 2019 at 1:28 AM João Matos <[email protected]> wrote:
> Hello,
>
> I would like to propose that instead of using this (applies to Py3.5 and
> upwards)
> dict_a = {**dict_a, **dict_b}
>
> we could use
> dict_a = dict_a + dict_b
>
> or even better
> dict_a += dict_b
>
>
> Best regards,
>
> João Matos
>
> _______________________________________________
> Python-ideas mailing list
> [email protected]
> https://mail.python.org/mailman/listinfo/python-ideas
> Code of Conduct: http://python.org/psf/codeofconduct/
>
--
INADA Naoki <[email protected]>
_______________________________________________
Python-ideas mailing list
[email protected]
https://mail.python.org/mailman/listinfo/python-ideas
Code of Conduct: http://python.org/psf/codeofconduct/
