There is already a much simpler way of doing this:
> try:
> i = int("string")
> except ValueError as e:
> print(e)
> print("continued on")
> j = int(9.0)
>
> The point of the 'try' block is to encapsulate the code you want to *stop*
> executing if an exception is raised. If you want code to be run regardless
> of whether an exception is raised, move it past the try-except.
>
To be fair, I suspect the issue was there were two calls to int() there
that might raise a ValueError, and the OP wanted to catch them with one
except, so you would need to do somethign like:
try:
i = int("string")
except ValueError as e:
print(e)
print("continued on")
try:
j = int(9.0)
except ValueError as e:
print(e)
Which can seem a bit verbose, but in fact, there are a number of ways one
might want to proceed with/without an error, and the current except,
finally, else options cover them all in a clearly defined way.
-CHB
>
> ~Amber
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