[issue10139] regex A|B : both A and B match, but B is wrongly preferred

[Christos Georgi ou]

Χρήστος Γεωργίου (Christos Georgiou) <t...@users.sourceforge.net> added the 
comment:

For completeness' sake, I also provide the "(?:regex_n)" results:

>>> text= 'A***Z'
>>> re.compile('(?:(?<=^A).*(?=Z$))').search(text).group(0) # regex_1
'***'
>>> re.compile('(?:(?<=^A).*)').search(text).group(0) # regex_2
'***Z'
>>> re.compile('(?:.*(?=Z$))').search(text).group(0) # regex_3
'A***'
>>> re.compile('(?:(?<=^A).*(?=Z$))|(?:(?<=^A).*)').search(text).group(0) # 
>>> regex_1|regex_2
'***'
>>> re.compile('(?:(?<=^A).*(?=Z$))|(?:.*(?=Z$))').search(text).group(0) # 
>>> regex_1|regex_3
'A***'
>>> re.compile('(?:(?<=^A).*)|(?:.*(?=Z$))').search(text).group(0) # 
>>> regex_2|regex_3
'A***'
>>> re.compile('(?:(?<=^A).*(?=Z$))|(?:(?<=^A).*)|(?:.*(?=Z$))').search(text).group(0)
>>>  # regex_1|regex_2|regex_3
'A***'

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<http://bugs.python.org/issue10139>
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