Georg Brandl <ge...@python.org> added the comment:
(This is not specific to running with -m, it occurs as well when you do "python
a.py b.py".)
The issue here is your call to exec() does not execute the code as its own
module. It executes the code as part of the main() function in a.py, with
(since you don't give a global namespace argument) the same global namespace as
that of a.main(), and there is no "sys" in that namespace. Further, the
compiler cannot treat b.main like a nested function of a.main (which would then
create a closure over the "sys" imported inside a.main). Therefore, the
reference to sys is treated as a global and not found.
If you give the exec() function an explicit dictionary as the globals argument,
this "works":
def main():
d = {'__name__': '__main__'}
exec(compile(open(sys.argv[1]).read(), sys.argv[1], 'exec'), d)
----------
nosy: +georg.brandl
resolution: -> wont fix
status: open -> closed
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue10129>
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