R. David Murray <rdmur...@bitdance.com> added the comment: locals() does not give you a copy of the locals dictionary that you can modify and expect the values to affect the actual locals they were copied from. This is documented:
http://docs.python.org/library/functions.html#locals You would need to pass InteractiveInterpreter the "real" locals dict from the frame to make your code work, and it sounds like you've already done this. However, I don't believe that this is going to work in the general case (eg: in the face of nested scopes), which is why locals() is not updatable. The use case for InteractiveInterpreter is implementing a python-command-line-like utility, and thus has no need to update the locals in the current function. A doc note about this in InteractiveInterpreter along the lines of the one in the 'exec' docs is almost certainly appropriate, so I'll leave this open as a doc bug. ---------- assignee: -> d...@python components: +Documentation -Interpreter Core nosy: +d...@python stage: -> needs patch versions: +Python 2.7, Python 3.1, Python 3.2 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue9274> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
