anatoly techtonik <techto...@gmail.com> added the comment:
webbrowser.open("%s:%s" % (HOST,PORT))
File "C:\Python25\lib\webbrowser.py", line 61, in open
if browser.open(url, new, autoraise):
File "C:\Python25\lib\webbrowser.py", line 518, in open
os.startfile(url)
WindowsError: [Error -2147217406] Windows Error 0x80041002: '127.0.0.1:8080'
I do not mind if new Python would handle this exception correctly, but it
doesn't launching wrong browser. If I specify "http://"; prefix - the Chrome
launched as expected. Note that if "127.0.0.1:8080" is executed from shell
(search menu or run dialog) - IE is not started by Vista.
----------
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue8936>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
