New submission from Dave Abrahams <d...@boostpro.com>: Based on the rsplit documentation, I'd expect
'foo bar'.rsplit(maxsplit=1) to work. This is probably a much bigger problem than just rsplit, i.e. I doubt there is a policy about whether documented parameter names need to be usable as keywords, and if not, how one finds out which keywords are supported. ---------- messages: 105040 nosy: dabrahams priority: normal severity: normal status: open title: TypeError: rsplit() takes no keyword arguments _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue8626> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
