New submission from Eric Smith <e...@trueblade.com>:
Sean Reifschneider proposed [1] adding the ability to log an exception using
the syslog module.
My proposed implementation is along the lines of:
def logexceptions(chain=True):
import sys
import traceback
import syslog
# Should we chain to the existing sys.excepthook?
current_hook = sys.excepthook if chain else None
def syslog_exception(etype, evalue, etb):
if current_hook:
current_hook(etype, evalue, etb)
# The result of traceback.format_exception might contain
# embedded newlines, so we have the nested loops.
for line in traceback.format_exception(etype, evalue, etb):
for line in line.rstrip().split('\n'):
syslog.syslog(line)
sys.excepthook = syslog_exception
Although it would need to be written in C to work in the existing syslog
module, and of course it would call syslog.syslog directly.
[1] http://mail.python.org/pipermail/python-ideas/2010-March/006927.html
----------
messages: 101605
nosy: eric.smith, jafo
priority: normal
severity: normal
stage: needs patch
status: open
title: Add exception logging function to syslog module
type: feature request
versions: Python 2.7, Python 3.2
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue8214>
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