Anand B Pillai <abpil...@gmail.com> added the comment: The issue is present in Python 3.0 and 2.5 as well.
Python 2.5.1 (r251:54863, Jul 17 2008, 13:21:31) [GCC 4.3.1 20080708 (Red Hat 4.3.1-4)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import datetime >>> t0=datetime.datetime(1,1,1) >>> d1,d2,d3=map(datetime.timedelta, range(1,4)) >>> t0-d1 Traceback (most recent call last): File "<stdin>", line 1, in <module> OverflowError: date value out of range >>> t0-d2 datetime.datetime(1, 0, 255, 0, 0) I think this is bug in datetime for all Python versions ---------- nosy: +pythonhacker _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue7150> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
