Mark Dickinson <dicki...@gmail.com> added the comment:
I think the calcsize result is correct here. With the native struct
format, padding is included in the struct.
In the second case, there are three bytes of padding after the 'cc' and
before the 'i'. This keeps the 'i' aligned on a 4-byte boundary. If you
look at the results of struct.pack, you can see the padding explicitly:
Python 2.6.1 (r261:67515, Jul 7 2009, 23:51:51)
[GCC 4.2.1 (Apple Inc. build 5646)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import struct
>>> struct.pack('ihhi35scci', 123456789, 10000, 10000, 321456789,
"abcdefghijklmnopqrstuvwxyz123456789", '+', '*', 231456789)
"\x15\xcd[\x07\x10'\x10'\x95\n)\x13abcdefghijklmnopqrstuvwxyz123456789+*\x
00\x00\x00\x15\xc0\xcb\r"
----------
nosy: +mark.dickinson
resolution: -> invalid
status: open -> closed
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue7189>
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