Amaury Forgeot d'Arc <amaur...@gmail.com> added the comment:
When the parser analyzes the test() function, it determines that 'u' in
"print(u)" is a global variable. But exec modifies the local namespace...
You could add a "u=None" near the start of the function, or better,
always use a namespace for the exec statement:
d = {}
exec v1 in d
en = d['u']
----------
nosy: +amaury.forgeotdarc
resolution: -> works for me
status: open -> closed
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue6862>
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