New submission from Adam Hopkins <a...@amhopkins.com>:
I believe the following produces an unexpected behavior:
from inspect import getsource
def bar(*funcs):
def decorator(func):
return func
return decorator
@bar(lambda x: bool(True), lambda x: False)
async def foo():
...
print(getsource(foo))
The output shows only the decorator declaration and none of the function:
@bar(lambda x: bool(True), lambda x: False)
>From my investigation, it seems like this requires the following conditions to
>be true:
- lambdas are passed in decorator arguments
- there is more than one lambda
- at least one of the lambdas has a function call
Passing the lambdas as default function arguments seems okay:
async def foo(bar=[lambda x: bool(True), lambda x: False]):
...
A single lambda seems okay:
@bar(lambda x: bool(True))
async def foo():
...
Lambdas with no function calls also seem okay:
@bar(lambda x: not x, lambda: True)
async def foo():
...
Tested this on:
- Python 3.10.2
- Python 3.9.9
- Python 3.8.11
- Python 3.7.12
----------
messages: 414149
nosy: ahopkins2
priority: normal
severity: normal
status: open
title: inspect.getsource with some lambdas in decorators does not get the full
source
versions: Python 3.10, Python 3.7, Python 3.8, Python 3.9
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue46873>
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