Eric V. Smith <e...@trueblade.com> added the comment:
The "evaluate the target" part causes the UnboundLocalError, just as in: >>> x=1 >>> def f(): ... x ... x = x + 1 ... >>> f() Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<stdin>", line 2, in f UnboundLocalError: local variable 'x' referenced before assignment ---------- nosy: +eric.smith _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue46612> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
