Serhiy Storchaka <storchaka+cpyt...@gmail.com> added the comment:
The drawback of that recipe of partition() is that it calls predicate twice on
every element. The following implementation calls it only once for every
element:
def partition(pred, iterable):
t1, t2 = tee((bool(pred(x)), x) for x in iterable)
return (x for p, x in t1 if not p), (x for p, x in t1 if p)
but it may be less efficient for fast predicates.
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nosy: +serhiy.storchaka
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue43899>
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