New submission from Tenzin <tenzin_c...@mymail.sutd.edu.sg>:
When using a `defaultdict` as a kwarg to a function that requires another
argument, every call to the function uses the same dictionary instance instead
of creating a new one.
```>>> from collections import defaultdict
>>> def meow(a, b=defaultdict(list)):
... b[a].append('moo')
... return b
...
>>> c = meow('hi')
>>> c
defaultdict(<class 'list'>, {'hi': ['moo']})
>>> c = meow('bye')
>>> c
defaultdict(<class 'list'>, {'hi': ['moo'], 'bye': ['moo']})
>>> d = meow('hello')
>>> d
defaultdict(<class 'list'>, {'hi': ['moo'], 'bye': ['moo'], 'hello':
['moo']})```
Is this the correct behaviour? Occurred in 3.6.12, 3.7.9, 3.8.5, 3.8.6 and
3.9.0.
----------
messages: 389289
nosy: TenzinCHW
priority: normal
severity: normal
status: open
title: Using defaultdict as kwarg to function reuses same dictionary every
function call
type: behavior
versions: Python 3.9
_______________________________________
Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue43589>
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