Serhiy Storchaka <storchaka+cpyt...@gmail.com> added the comment:
Funny. But the output is not random. You can generate the sequence of letters by the following simple loop: s = '' for i in range(n): s = f'a{s}b{s}' The length of this sequence is 2*(2**n-1). Finally, your code will raise a non-silenced RecursiveError, but it will just take some time (for printing around 2**1000 letters). ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue42951> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com