New submission from Artyom Kaltovich <kaltovichart...@gmail.com>:
Hello. At first I want to say thank you for all your efforts in python development. I really appreciate it. :) I am trying to convert custom object to json. But, I've found a problem. JSONEncoder has ``default`` method for converting custom objects to some primitives and ``encode`` for converting structures. But what if I want to return completed json string? I can't do it in ``default``, because JSONEncoder will think it is string and encode it accordingly later in ``iterencode`` method. Then I tried redefine encode, but it is called with the dict(array_name=default(o)) so I should convert the dict as a whole and basically reimplement all conversions (for int, float, and lists of course). Did I missed something or there is no way to do it? I suggest to introduce another method, e.g. encode_obj and call it there: https://github.com/python/cpython/blob/master/Lib/json/encoder.py#L438 ``` o = _default(o) yield from _iterencode(o, _current_indent_level) ``` -> ``` o = _encode_obj(_default(o)) yield from _iterencode(o, _current_indent_level) ``` If you are agree I would be happy to implement it. Best Regards, Artsiom. ---------- components: Library (Lib) messages: 384085 nosy: kaltovichartyom priority: normal severity: normal status: open title: There is no way to json encode object to str. _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue42791> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
