Raymond Hettinger <raymond.hettin...@gmail.com> added the comment:
This should stay closed as a duplicate.
If you must, reopen of the original 27071, but it was closed for a reason. The
majority of respondents voted for the status quo. Each alternative that was
considered had its own share of problems.
BTW, it is hyperbolic to call the name "horribly misleading". The method
literally runs Counter and checks for equality. The docstring is clear about
this:
def assertCountEqual(self, first, second, msg=None):
"""Asserts that two iterables have the same elements, the same number of
times, without regard to order.
self.assertEqual(Counter(list(first)),
Counter(list(second)))
Example:
- [0, 1, 1] and [1, 0, 1] compare equal.
- [0, 0, 1] and [0, 1] compare unequal.
"""
----------
nosy: +rhettinger
status: open -> closed
_______________________________________
Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue38240>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
