Quentin Wenger <wenger.quen...@bluewin.ch> added the comment:
I prove my point that the decoding to string is arbitrary:
```
>>> import re
>>> orig_name = "Ř"
>>> orig_ch = orig_name.encode("cp1250") # Because why not?
>>> name = list(re.match(b"(?P<" + orig_ch + b">)", b"").groupdict().keys())[0]
>>> name == orig_name
False
>>> name
'Ø'
>>> name.encode("latin-1") == orig_ch
True
```
For any dynamically-constructed bytes regex pattern, a string group name as
output is unusable. Only after latin-1-reencoding can it be safely compared.
This latin-1 choice is arbitrary.
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue40980>
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