[issue39805] Copying functions doesn't actually copy them

[Steven D'Aprano]

Steven D'Aprano <steve+pyt...@pearwood.info> added the comment:

I think this is sufficient for a shallow copy.

import copy
import types

def copyfunction(func):
    new = types.FunctionType(
            func.__code__,
            func.__globals__,
            func.__name__,
            func.__defaults__,
            func.__closure__
            )
    vars(new).update(vars(func))
    new.__annotations__.update(func.__annotations__)
    if func.__kwdefaults__ is not None:
        new.__kwdefaults__ = func.__kwdefaults__.copy()
    return new

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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue39805>
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