Steven D'Aprano <steve+pyt...@pearwood.info> added the comment:
I agree with both Eric and Zachary, but I just wanted to point out that in a
Python interpreter with a keyhole optimizer, you can expect that expressions
like `1*10**9` to be a constant:
# Python 3.5
py> from dis import dis
py> dis('1*10**9')
1 0 LOAD_CONST 4 (1000000000)
3 RETURN_VALUE
Marco, if you are worried about the performance cost of multiplying by a power
of ten when creating constants, you shouldn't.
----------
nosy: +steven.daprano
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue39788>
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