David Zaslavsky <diazona...@ellipsix.net> added the comment: I just had the same problem in a call to inspect.findsource() (actually my code calls inspect.stack() which calls ... which calls findsource()). The code object passed to findsource() had a filename of "database/__init__.py" which is the correct filename relative to sys.path, so in this case a simple fix would have worked: delete line 82 of linecache.py 82 basename = os.path.split(filename)[1] and use filename instead of basename for the rest of the function. (Or for a quick hack, change line 82 to just "basename = filename")
I'm using Python 2.5.2 but the relevant code in linecache.py also exists in 3.0 (just checked). ---------- nosy: +diazona versions: +Python 3.0 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue1309567> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
