Zachary Ware <zachary.w...@gmail.com> added the comment:
For `list1`, you are creating three separate lists containing `0` contained by a fourth list. For `list2`, you're creating a single list containing `0` contained by a second list, and then replicating the contents of that second list three times; thus `list2` actually contains the same list object three times. You can compare the result of `[id(l) for l in list1]` with the same for `list2` to see this. See point 2 here [1] and in this [2] FAQ for more information on this. [1] https://docs.python.org/3/library/stdtypes.html#common-sequence-operations [2] https://docs.python.org/3/faq/programming.html#faq-multidimensional-list ---------- nosy: +zach.ware resolution: -> not a bug stage: -> resolved status: open -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue39403> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
