Steven D'Aprano <steve+pyt...@pearwood.info> added the comment:
"should dict preemptively make sure it doesn't accept a sequence of sets"
No. The person on StackOverflow made a mistake in their code: they used an
unordered data structure (set) instead of an ordered data structure (tuple):
dict({i,j} for i,j in enumerate(lst))
It is a waste of time to slow down the dict constructor to check for something
so unusual as this. Everyone will pay the cost of the checks and virtually
no-one will get any benefit.
I'm closing this as "rejected", but if anyone disagrees they can reopen it.
By the way, the best way to initialise a dictionary in this situation is to
avoid the unnecessary generator expression and just go straight to enumerate:
dict(enumerate(lst))
----------
nosy: +steven.daprano
resolution: -> rejected
stage: -> resolved
status: open -> closed
_______________________________________
Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue39178>
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