Zachary Ware <zachary.w...@gmail.com> added the comment:
It's not clear what you're asking for here. Your example works, though the contents of `a` and `c` will each be an arbitrary member of S and `b` the rest of the members of S and you have no guarantee of what you'll get. If you want to be sure of what each name will be attached to, just do `a, *b, c = sorted(S)`. ---------- nosy: +zach.ware _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue38855> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
