STINNER Victor <vstin...@redhat.com> added the comment:
Changing dict.update() calling convention may save a few nanoseconds on d1.update(d2) call, but it will make d1.update(**d2) way slower with a complexity of O(n): d2 must be converted to 2 lists (kwnames and args) and then a new dict should be created. I don't see the point of micro-optimizing d1.update(d2), if d1.update(**d2) would become way slower. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue29312> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
