New submission from Siming Yuan <simin...@gmail.com>:
Using os.execl you can open a new bash shell (eg, using python to process some
env before opening a new shell.
$ echo $SHLVL
1
$ ~/.pyenv/versions/3.6.4/bin/python3
Python 3.6.4 (default, Feb 5 2018, 16:53:35)
[GCC 4.2.1 Compatible Apple LLVM 9.0.0 (clang-900.0.39.2)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import os
>>> os.execl('/bin/bash', '')
$ echo $SHLVL
2
Doing the above works with just /bin/bash no arguments. (notice SHLVL
incrementing)
But providing your own custom --init-file or --rcfile, doesn't.
eg - /bin/bashrc --rcfile <path to a venv activate file>
$ echo $SHLVL
1
$ ~/.pyenv/versions/3.6.4/bin/python3
Python 3.6.4 (default, Feb 5 2018, 16:53:35)
[GCC 4.2.1 Compatible Apple LLVM 9.0.0 (clang-900.0.39.2)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import os
>>> os.execl('/bin/bash', '--rcfile','/users/me/venv/bin/activate')
$ echo $SHLVL
1
this can be replicated in Python 3.5 to 3.7
can be worked-around if using a wrapper.sh file with:
#! /bin/bash
exec /bin/bash --rcfile /users/me/venv/bin/activate
and running this file in os.execl() instead.
----------
messages: 343654
nosy: siming85
priority: normal
severity: normal
status: open
title: os.execl opening a new bash shell doesn't work if initfile/rcfile
provided
versions: Python 3.5, Python 3.6, Python 3.7
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue37066>
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