Stéphane Wirtel <steph...@wirtel.be> added the comment: Python 3.7.2 (default, Jan 16 2019, 19:49:22) [GCC 8.2.1 20181215 (Red Hat 8.2.1-6)] on linux Type "help", "copyright", "credits" or "license" for more information. >>> import re >>> s = '[a]' >>> print(*re.findall(r'\[.*]', s)) [a] >>> print(*re.findall(r'\[.*]', s)) [a] >>>
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