Dragoljub <dragol...@gmail.com> added the comment:
Here is a simple pure python example: digits = ''.join([str(i) for i in range(10)]*10000000) %timeit digits.isdigit() # --> 2X+ slower on python 3.7.1 Basically in Pandas C-code parser we call the isdigit() function for each number that is to be parsed. so 12345.6789 calls isdigt() 9 times to determine if this is a digit character that can be converted to a float. The problem is in the latest version of Python with locale updates isdigit() takes a locale argument that seems to be passed over and over slowing down this check. Is it possible that we disable any local passing from Python down to lower-level C code, or simply set the default locale to 'C' to keep it from thrashing? ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue35195> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
