New submission from Dan Boxall <dbox...@l3mtechnologies.com>:
Hi, I'm new to regular expressions and while playing around with them I tried
this:
>>> rex = '*New Revision:.* ([0-9]+)'
>>> re.findall(rex, text)
and got this:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Python\Python37\lib\re.py", line 223, in findall
return _compile(pattern, flags).findall(string)
File "C:\Python\Python37\lib\re.py", line 286, in _compile
p = sre_compile.compile(pattern, flags)
File "C:\Python\Python37\lib\sre_compile.py", line 764, in compile
p = sre_parse.parse(p, flags)
File "C:\Python\Python37\lib\sre_parse.py", line 930, in parse
p = _parse_sub(source, pattern, flags & SRE_FLAG_VERBOSE, 0)
File "C:\Python\Python37\lib\sre_parse.py", line 426, in _parse_sub
not nested and not items))
File "C:\Python\Python37\lib\sre_parse.py", line 651, in _parse
source.tell() - here + len(this))
re.error: nothing to repeat at position 0
----------
components: Regular Expressions
messages: 329130
nosy: Callipygean, ezio.melotti, mrabarnett
priority: normal
severity: normal
status: open
title: Bad Regular Expression Broke re.findall()
versions: Python 3.7
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue35146>
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