Tim Peters <t...@python.org> added the comment:
This doesn't actually matter - the code can never trigger. It would be fine to replace it with an assert to that effect (see below for a specific suggestion). The reason: The indices in this code are into vectors of PyObject*. These vectors can't contain more than floor(PY_SSIZE_T_MAX / sizeof(PyObject*)) pointers (see listobject.c & Python's heap allocation routines). So the largest legit index this code can ever see is 1 less than that. Since pointers are at least 4 bytes on all machines Python runs on, that implies (with room to spare) that assert(ofs <= (PY_SSIZE_T_MAX - 1) / 2); can't fail. Which in turn implies that, mathematically, 2*ofs + 1 <= PY_SSIZE_T_MAX So if (ofs <= 0) /* int overflow */ can't happen, regardless of how the platform C treats signed overflow (signed overflow can't happen to begin with). The existing `while (ofs < maxofs)` check already ensures that `ofs` is a legit index, and _any_ legit index into a PyObject* vector can be doubled and incremented without overflowing Py_ssize_t. In fact, that would remain so even if listobject.c allowed its PyObject* vectors to contain twice as many pointers as they actually can contain now. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue35091> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com