ppperry <maprea...@olum.org> added the comment:
Your PR is not an improvement: 1. In this case, this will produce the error "tuple.__new__(sys.flags) is not safe". But I didn't call "tuple.__new__", I called sys.flags.__new__, and type(X).__new__(type(X)) should always be safe 2. The change in error message for namedtuples (A) isn't related and (B) isn't correct. `tuple.__new__(NamedTuple)` works, and produces a namedtuple object, so tuple.__new__ is what the error should point to. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue34284> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
