STINNER Victor <vstin...@redhat.com> added the comment:
Is there really an use case which requires to set the permission of the file created by uu.decode()? It is already possible to call uu.decode() with an open file which has been created with the expected permission. Moreover, it's also possible to explicitly call chmod() *after* uu.decode(). I would suggest to deprecate the mode parameter in Python 3.7 and remove it from Python 3.8. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue33687> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
