New submission from Antony Lee <anntzer....@gmail.com>:
Python 3.6.4
In [15]: inspect.Parameter("foo", kind=inspect.Parameter.VAR_KEYWORD,
default=42)
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-15-7ed8c4fd15f3> in <module>()
----> 1 inspect.Parameter("foo", kind=inspect.Parameter.VAR_KEYWORD,
default=42)
/usr/lib/python3.6/inspect.py in __init__(self, name, kind, default,
annotation)
2442 if kind in (_VAR_POSITIONAL, _VAR_KEYWORD):
2443 msg = '{} parameters cannot have default
values'.format(kind)
-> 2444 raise ValueError(msg)
2445 self._default = default
2446 self._annotation = annotation
ValueError: 4 parameters cannot have default values
Note the "interesting" error message that starts with "4 parameters ..." (yes,
I guess that inspect.Parameter == 4 internally...).
Probably just a matter of making the error f'{kind.name} parameters ...'.
----------
components: Library (Lib)
messages: 314764
nosy: Antony.Lee
priority: normal
severity: normal
status: open
title: Confusing error message when constructing invalid inspect.Parameters
versions: Python 3.6
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue33197>
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