Terry J. Reedy <tjre...@udel.edu> added the comment:
I did take the code, and it would not run because of the indent. With that
fixed, it still did not run because the the indent in the quoted code fed to
exec. This does run:
import builtins
class K(dict):
def __getitem__(self, k):
if k not in builtins.__dict__:
print("get %s" % k)
return dict.__getitem__(self, k)
def __setitem__(self, k, v):
print("set %s" % k)
dict.__setitem__(self, k, v)
exec("""
foo = "bar"
foo
try:
qyz
except NameError:
pass
class K:
baz = foo
def f(ggg=foo): pass
def g(ggg=foo):
global f
f = 87
f
g()
""", K())
When I run in IDLE, which execs the entire code, so none is run at module
level, I get the same result. The same is true running directly in Python
after wrapping the entire code with
exec('''
# and
''')
In this case, nothing other than the outer exec is run at module level. So I
am not sure there is a bug. If you don't get a more definitive response here,
I suggest posting to python-list for opinions on whether bug or feature.
----------
nosy: +terry.reedy
_______________________________________
Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue32615>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
