New submission from David MacIver <david.maci...@gmail.com>: The documentation for the UUID module says the UUID.version field is "The UUID version number (1 through 5, meaningful only when the variant is RFC_4122)".
However, the UUID constructor doesn't actually validate that the version lies in that range if you don't pass a version to the constructor and, as a result, this isn't actually true - the version number can be anything between 0 and 15. For an example consider the following: >>> from uuid import UUID >>> u = UUID(int=1133377179260751706062848) >>> u.variant 'specified in RFC 4122' >>> u.version 15 I have only actually run this example on Python 3.6, but inspection of the code suggests that it's been like this since its introduction. ---------- components: Library (Lib) messages: 305636 nosy: David MacIver priority: normal severity: normal status: open title: UUID versions: Python 2.7, Python 3.4, Python 3.5, Python 3.6 _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue31958> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
