Christoph Reiter added the comment:
Why not just do the following:
>>> from collections import namedtuple
>>> Point = namedtuple('Point', ['x', 'y'])
>>> Point._source
"from collections import namedtuple\nPoint = namedtuple('Point', ['x', 'y'])\n"
>>>
The docs make it seems as if the primary use case of the _source attribute is
to serialize the definition. Returning a source which produces a class with
different performance/memory characteristics goes against that.
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nosy: +lazka
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue28638>
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