Raymond Hettinger added the comment: Sorry, this is just how expression lists work. See Grammar/Grammar at https://hg.python.org/cpython/file/tip/Grammar/Grammar
This is really no different than: for [k] is s: ... or: [k, j] = s > Why not set literals Because sets are unordered and because it isn't needed. ---------- nosy: +rhettinger resolution: -> not a bug stage: -> resolved status: open -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue30402> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com