Christian Heimes added the comment: Here is another example of how broken and dangerous fileno argument is. getpeername() is neither a valid IPv4 tuple nor a valid IPv6 tuple. It's all messed up:
>>> import socket >>> s = socket.create_connection(('www.python.org', 443)) >>> s <socket.socket fd=3, family=AddressFamily.AF_INET6, type=SocketKind.SOCK_STREAM, proto=6, laddr=('2003:58:bc4a:3b00:56ee:75ff:fe47:ca7b', 59730, 0, 0), raddr=('2a04:4e42:1b::223', 443, 0, 0)> >>> socket.socket(fileno=s.fileno()) <socket.socket fd=3, family=AddressFamily.AF_INET, type=SocketKind.SOCK_STREAM, proto=0, laddr=('2003:58:bc4a:3b00::%2550471192', 59730, 0, 2550471192), raddr=('2a04:4e42:1b:0:700c:e70b:ff7f:0%2550471192', 443, 0, 2550471192)> ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue28134> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com