Serhiy Storchaka added the comment: The default value of the lower bound index is 0, but the default value of the upper bound index is the length of the sequence. s[:a] is the same as s[0:a], but s[a:] is the same as s[a:len(s)].
If make s[a:0] meaning the same as s[a:len(s)], i.e. return a subsequence from index a to the end, while s[0:a] means the same as s[:a], i.e. returns a subsequence from the begin to index a, what should mean s[0:0]? There is a contradiction. This change would break existing code. ---------- nosy: +serhiy.storchaka resolution: -> rejected stage: -> resolved status: open -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue28336> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
