New submission from James Domingo: The platform.release() function in Python 3.5.1 returns the correct value on Windows 2008 Server R2:
C:\Users\jdoe\Documents\Python>python-3.5.1-embed-amd64\python.exe Python 3.5.1 (v3.5.1:37a07cee5969, Dec 6 2015, 01:54:25) [MSC v.1900 64 bit (AM D64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import platform >>> platform.release() '2008ServerR2' However, the function in the latest release, Python 3.5.2, misidentifies the system as Windows 7: C:\Users\jdoe\Documents\Python>python-3.5.2-embed-amd64\python.exe Python 3.5.2 (v3.5.2:4def2a2901a5, Jun 25 2016, 22:18:55) [MSC v.1900 64 bit (AM D64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import platform >>> platform.release() '7' ---------- components: Library (Lib) messages: 273890 nosy: James Domingo priority: normal severity: normal status: open title: platform.release() incorrect in Python 3.5.2 on Windows 2008ServerR2 type: behavior versions: Python 3.5 _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue27890> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
