R. David Murray added the comment:
It seems perfectly logical and consistent to me. {4} is a repeat count, as is
*. You get the same error if you do 'a?*', and the same bypass if you do
'(a?)*' (though I haven't tested if that does anything useful :). You don't
need the ?:, as far as I can tell, you just need to have the * modifying a
group, making the group the "preceding regular expression".
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nosy: +r.david.murray
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue27800>
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